What we want to know is how many pairs of jeans we want to buy (let’s say “\(j\)”) and how many dresses we want to buy (let’s say “\(d\)”). This will help us decide what variables (unknowns) to use. The first trick in problems like this is to figure out what we want to know. Now, you can always do “guess and check” to see what would work, but you might as well use algebra! It’s much better to learn the algebra way, because even though this problem is fairly simple to solve, the algebra way will let you solve any algebra problem – even the really complicated ones. How many pairs of jeans and how many dresses you can buy so you use the whole $200 (tax not included)? You really, really want to take home 6 items of clothing because you “need” that many new things. You discover a store that has all jeans for $25 and all dresses for $50. You’re going to the mall with your friends and you have $200 to spend from your recent birthday money. Let’s say we have the following situation: So far, we’ve basically just played around with the equation for a line, which is \(y=mx+b\). “Systems of equations” just means that we are dealing with more than one equation and variable. Note that we solve Algebra Word Problems without Systems here, and we solve systems using matrices in the Matrices and Solving Systems with Matrices section here. Inequality Word Problem (in Linear Programming section)
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